Arithmetic and Geometric Progressions
Tags: #math #arithmetic #geometric #progressionsEquation
$$S_{n}=a+(a+d)+(a+2d)+...+[a+(n-1)d]=\frac{n}{2}[2a+(n-1)d] \\ S_{n}=a+ar+ar^{2}+...+ar^{n-1}=a\frac{1-r^{n}}{1-r}$$Latex Code
S_{n}=a+(a+d)+(a+2d)+...+[a+(n-1)d]=\frac{n}{2}[2a+(n-1)d] \\ S_{n}=a+ar+ar^{2}+...+ar^{n-1}=a\frac{1-r^{n}}{1-r}
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Introduction
Explanation
. The first number is a, and the consecutive series number follows the pattern of
at the number at the (n-1) th position is
.
. The first number is a, and the consecutive series number follows the pattern of
with multiplier as r and at the the number at (n-1) th position is
.
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