The Uncertainty Principle
Tags: #physics #quantumEquation
$$(\Delta A)^2=\left\langle \psi|A_{\rm op}-\left\langle A \right\rangle|^2\psi \right\rangle=\left\langle A^2 \right\rangle-\left\langle A \right\rangle^2 \\ \Delta A\cdot\Delta B\geq \frac{1}{2} |\left\langle \psi|[A,B]|\psi \right\rangle| \\ \Delta E\cdot\Delta t\geq\hbar \\ \Delta p_x\cdot\Delta x\geq \frac{1}{2} \hbar \\ \Delta L_x\cdot\Delta L_y\geq \frac{1}{2} \hbar L_z$$Latex Code
(\Delta A)^2=\left\langle \psi|A_{\rm op}-\left\langle A \right\rangle|^2\psi \right\rangle=\left\langle A^2 \right\rangle-\left\langle A \right\rangle^2 \\
\Delta A\cdot\Delta B\geq \frac{1}{2} |\left\langle \psi|[A,B]|\psi \right\rangle| \\
\Delta E\cdot\Delta t\geq\hbar \\
\Delta p_x\cdot\Delta x\geq \frac{1}{2} \hbar \\
\Delta L_x\cdot\Delta L_y\geq \frac{1}{2} \hbar L_z
Have Fun
Let's Vote for the Most Difficult Equation!
Introduction
Equation
Latex Code
(\Delta A)^2=\left\langle \psi|A_{\rm op}-\left\langle A \right\rangle|^2\psi \right\rangle=\left\langle A^2 \right\rangle-\left\langle A \right\rangle^2 \\
\Delta A\cdot\Delta B\geq \frac{1}{2} |\left\langle \psi|[A,B]|\psi \right\rangle| \\
\Delta E\cdot\Delta t\geq\hbar \\
\Delta p_x\cdot\Delta x\geq \frac{1}{2} \hbar \\
\Delta L_x\cdot\Delta L_y\geq \frac{1}{2} \hbar L_z
Explanation
Latex code for The Uncertainty Principle. I will briefly introduce the notations in this formulation.
: Uncertainty in A
Reply