De Moivre's Theorem
Tags: #math #complex number #De MoivreEquation
$$(\cos \theta + i \sin \theta)^{n}=e^{in\theta}=\cos n\theta + i \sin n\theta$$Latex Code
(\cos \theta + i \sin \theta)^{n}=e^{in\theta}=\cos n\theta + i \sin n\theta
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Introduction
Equation
Latex Code
(\cos \theta + i \sin \theta)^{n}=e^{in\theta}=\cos n\theta + i \sin n\theta
Explanation
: The power n of
equals to
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If I could have one wish, it would be to pass this exam.
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