Maclaurin Series Equation Formula Latex Code and Summary

Maclaurin Series

Tags: #math #maclaurin series

Equation

$$y(x)=y(a+u)=y(0)+x\frac{\mathrm{d} y}{\mathrm{d} x}+\frac{1}{2!}x^{2}\frac{\mathrm{d}^2 y}{\mathrm{d} x^{2}}+\frac{1}{3!}x^{3}\frac{\mathrm{d}^3 y}{\mathrm{d} x^{3}}+...$$

Latex Code

                                 y(x)=y(a+u)=y(0)+x\frac{\mathrm{d} y}{\mathrm{d} x}+\frac{1}{2!}x^{2}\frac{\mathrm{d}^2 y}{\mathrm{d} x^{2}}+\frac{1}{3!}x^{3}\frac{\mathrm{d}^3 y}{\mathrm{d} x^{3}}+...

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Introduction

$y(x)=y(a+u)=y(0)+x\frac{\mathrm{d} y}{\mathrm{d} x}+\frac{1}{2!}x^{2}\frac{\mathrm{d}^2 y}{\mathrm{d} x^{2}}+\frac{1}{3!}x^{3}\frac{\mathrm{d}^3 y}{\mathrm{d} x^{3}}+...$

Latex code for Maclaurin Series

$u$ : u=x-a
$n!$ : Factorials of n
$\frac{\mathrm{d}^{n} y}{\mathrm{d} x^{n}}$ : Derivative of y over x evaluated at point x=a

When u=x-a, the differential coefficients are evaluated at x=a. A Maclaurin series is a Taylor series with a = 0

Discussion

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Melissa Clark

I'm geared up to pass this exam.

2024-02-26 00:00
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Kathy Young reply to Melissa Clark

Nice~

2024-03-24 00:00:00.0
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Ruth Edwards

Craving a victory on this upcoming test.

2023-11-04 00:00
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Ernest White reply to Ruth Edwards

You can make it...

2023-12-04 00:00:00.0
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Oscar Meyer

Anticipating a pass on this exam.

2023-04-04 00:00
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James Williams reply to Oscar Meyer

Gooood Luck, Man!

2023-04-25 00:00:00.0
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