Shear Modulus
Tags: #physics #mechanics #shear modulusEquation
$$M_{s} = \frac{F_{s} / A}{ {\Delta x} /L}=\frac{F_{s}/A}{\tan \theta}M_{s} = \frac{F_{s}/A}{\Delta x/L} = \frac{F_{s}/A}{\tan \theta}$$Latex Code
M_{s} = \frac{F_{s} / A}{ {\Delta x} /L}=\frac{F_{s}/A}{\tan \theta}M_{s} = \frac{F_{s}/A}{\Delta x/L} = \frac{F_{s}/A}{\tan \theta}
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Introduction
Equation
Latex Code
M_{s} = \frac{F_{s} / A}{ {\Delta x} /L}=\frac{F_{s}/A}{\tan \theta}M_{s} = \frac{F_{s}/A}{\Delta x/L} = \frac{F_{s}/A}{\tan \theta}
Explanation
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